A body of mass 5 kg falls from the rest from a height 10 metre from earth surface the kinetic energy of a body on the earth surface will be
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Given
m = 5kg. , s = h = 10 m , u =0 , a= 9.8 m/s^2 = g
Solution
v^2 = u^2 + 2as
v^2 = 0 + 2 ×9.8 × 10
= 196 m/s
Velocity square = 196 m/s
Kinetic energy = 1/2 mv^2
Kinetic energy = 1/2 × 5 × 196
Therefore, Kinetic energy is 490 J.
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