A body of mass 5 kg has linear momentum of 20kgm/s. If a constant force of 5N acts on it in the direction of its motion for 10s. The change in kinetic energy of the body
Answer is 450J.
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Solution :
Given :
↪Mass = 5 kg
↪ Momentum = 50 kgm/s
↪ Force = 5 N
↪ Time = S
Solution :
P( Momentum ) = m × v
20 kg m/s = 5 kg × v
•°• v = 20 kg m/s ÷ 5 kg
v = 4 m/s
Lets find out velocity after 10 Second !
{ v = u + at }
↪v = u + (f/m)t
↪v2= v1 + ( 5/5 * 10 )
↪v2 = 4 + ( 10 )
↪v2 = 14 m/s
Now, According to the Question!
Change in kinetic of the body = mv²/2 - mv²/2
mv²/2 - mv²/2
↪m/2 ( v2² - v1² )
↪5/2 ( 14²- 4² )
↪5/2 [ ( 4 + 14 ) ( 14 - 4 ) ]
↪5/2 [ ( 18 × 10 ) ]
↪5/2 × 180
↪5 × 90
↪450 joule
Given :
↪Mass = 5 kg
↪ Momentum = 50 kgm/s
↪ Force = 5 N
↪ Time = S
Solution :
P( Momentum ) = m × v
20 kg m/s = 5 kg × v
•°• v = 20 kg m/s ÷ 5 kg
v = 4 m/s
Lets find out velocity after 10 Second !
{ v = u + at }
↪v = u + (f/m)t
↪v2= v1 + ( 5/5 * 10 )
↪v2 = 4 + ( 10 )
↪v2 = 14 m/s
Now, According to the Question!
Change in kinetic of the body = mv²/2 - mv²/2
mv²/2 - mv²/2
↪m/2 ( v2² - v1² )
↪5/2 ( 14²- 4² )
↪5/2 [ ( 4 + 14 ) ( 14 - 4 ) ]
↪5/2 [ ( 18 × 10 ) ]
↪5/2 × 180
↪5 × 90
↪450 joule
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