A body of mass 5 kg has linear momentum of 20kgm/s. If a constant force of 5N acts on it in the direction of its motion for 10s. The change in kinetic energy of the body
Answer is 450J.
Answers
Answered by
20
Solution :
Given :
↪Mass = 5 kg
↪ Momentum = 50 kgm/s
↪ Force = 5 N
↪ Time = S
Solution :
P( Momentum ) = m × v
20 kg m/s = 5 kg × v
•°• v = 20 kg m/s ÷ 5 kg
v = 4 m/s
Lets find out velocity after 10 Second !
{ v = u + at }
↪v = u + (f/m)t
↪v2= v1 + ( 5/5 * 10 )
↪v2 = 4 + ( 10 )
↪v2 = 14 m/s
Now, According to the Question!
Change in kinetic of the body = mv²/2 - mv²/2
mv²/2 - mv²/2
↪m/2 ( v2² - v1² )
↪5/2 ( 14²- 4² )
↪5/2 [ ( 4 + 14 ) ( 14 - 4 ) ]
↪5/2 [ ( 18 × 10 ) ]
↪5/2 × 180
↪5 × 90
↪450 joule
Given :
↪Mass = 5 kg
↪ Momentum = 50 kgm/s
↪ Force = 5 N
↪ Time = S
Solution :
P( Momentum ) = m × v
20 kg m/s = 5 kg × v
•°• v = 20 kg m/s ÷ 5 kg
v = 4 m/s
Lets find out velocity after 10 Second !
{ v = u + at }
↪v = u + (f/m)t
↪v2= v1 + ( 5/5 * 10 )
↪v2 = 4 + ( 10 )
↪v2 = 14 m/s
Now, According to the Question!
Change in kinetic of the body = mv²/2 - mv²/2
mv²/2 - mv²/2
↪m/2 ( v2² - v1² )
↪5/2 ( 14²- 4² )
↪5/2 [ ( 4 + 14 ) ( 14 - 4 ) ]
↪5/2 [ ( 18 × 10 ) ]
↪5/2 × 180
↪5 × 90
↪450 joule
Similar questions