Question

a
body of mass 5 kg
in hung by a spring balance in a
lift.
Find the read
reading
of the balance when
The lift is moving downwards with an
acceleration of 1 m/s2
​

Answer 1

Answer:

m = 5kg

a = 1m/s^2

so the force is = m×a

f = 5×1

f = 5N ans