Question

A body of mass 5 kg,initial at rest ,is moved by a horizontal force of 2 Newton on a smooth horizontal surface, find the work done by a force in 10 second?​

Answer 1

Answer:

A = F/m a = 2/5 m/s² s=1/2at² (on the grounds that u is zero) s=1/2*2/5*10² s = 2/10*100 s = 20m w=F.S w=2*20 w=40 J.