Question

A body of mass 5 kg, initially at rest, is moved by a horizontal force of 10N on a smooth horizontal surface. Find the work done by the force in 5 seconds.
a.100J
b. 200J
c. 250J
d. 300J
e. NOT
answer is C
need solution​

Answer 1

Answer:

Force, F=10N

Mass, m=5Kg

Force,

F=ma

a=2m/s2

Work done, W=F.ds

In first second, displacement,

s=21at2

s=21×2×1

s=1m

So, work done,W=10×1=10J

In second second, s=21×2×4=4m

So, the displacement is , 4−1=3m

Hence, work done in 2 second is,

W=10×3

W=30J

Answer 2

Answer:

you can put your values in this question... hope this helps you dear