Question

A body of mass 5 kg is acted upon by two perpendicular forces 8N and 6 N. Give the magnitude and direction of the acceleration of the body.​

Answer 1

Given:-

• Mass of the body = 5kg
• Value of 1st perpendicular forces is 8N
• Value of 2nd perpendicular forces is 6N.

Refer to the attachement for more information.

The resultant force of two perpendicular forces is:-

➟ R = √8² + √(-6)²

➟ R = √64 + √36

➟ R = √100

➟ R = 10

And a is the angle that is made by R with the force of 8N .

So by using trigonometry,

We have,

➟ Tan a = P/B

➟ Tan a = 6/8

➟ a = tan –¹(6/8) = (-36.87)°

Here the negative sign in (-36.87)° indicates that a is in the classroom clockwise direction with respect to the force of 8N.

And by Newton's second law of motion,

F = ma

Where F is the force ,m be the mass and a be the acceleration.

So, we get

➟ 10 = 5×a

➟ 10/5 = a

➟ 2 m/s² = a

Therefore:-

The acceleration of the body is 2m/s² and the direction is in clockwise direction.

Answer 2

Explanation:

solution in the attachment