A body of mass 5 kg is acted upon by two perpendicular forces of
magnitude 8 N and 6 N. Find the magnitude and direction of the
acceleration.
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2
resultant force=√64+36=10
magnitude of acceleration=10/5=2
direction =tan theta=(8/5)/(6/5)=4/3
magnitude of acceleration=10/5=2
direction =tan theta=(8/5)/(6/5)=4/3
Answered by
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See the above attachment for better understanding.
Answer :
Magnitude of acc = 2 ms¯²
Direction is 37° from 8 N.
Solution :-
Resultant Force (R) = (8² + (- 6)²)^½
= 10 N
And the angle made from 8 N force = tan (6/8)=37°
Now by using Newton's second law, we get
- F = ma
- ma 10 = 5 × a
- a = 2 ms¯².
Attachments:
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