Question

a body of mass 5 kg is acted upon by two perpendicular forces 8N and 6 N . give the magnitude and direction of accleration of the body

Answer 1

Answer:-

Mass of the body, m = 5 kg
The given situation can be represented as follows:



The resultant of two forces is given as:



θ is the angle made by R with the force of 8 N
∴ θ = tan-1(-6/8) = -36.870
The negative sign indicates that θ is in the clockwise direction with respect to the force of magnitude 8 N.

As per Newton’s second law of motion, the acceleration (a) of the body is given as:
F = ma
∴ a = F / m = 10 / 5 = 2 ms-2

Answer 2

As,F= ma hence to find the magnitude of of force ,use law of cosin that is √ F1 + F2 +2F1F2Costheta then force comes to be 10 newton and mass is given as 5 kg so for acceleration the formula( F= ma) looks like ( a= F/m) and then put values to force =10 N and mass=5 kg and acceleration comes to be 2m/s2