Question

a body of mass 5 kg is at rest on a smooth horizontal surface a horizontal force f on it for 4 seconds and then creates to act if the body travels 40 metres in next 5 minutes the value of f is

Answer 1

Here f acts for 4 s.The change in impulse will be equal to m×v. Equating we get f=0.16N

Answer 2

Given that,

Mass of a body, m = 5 kg

Initial speed, u = 0

Time, t = 4 s

Distance, d = 40 m

To find,

The force acting on the body for next 5 minute.

Solution,

If F is force and a is acceleration, force is given by :

$F=ma\\\\a=\dfrac{F}{m}\\\\a=\dfrac{F}{5}$

Using equation of motion,

v = u +at

u = 0

$v=at\\\\v=\dfrac{4F}{5}$

Speed of the body is distance covered divided by time. So,

$\dfrac{4F}{5}=\dfrac{40}{5}\\\\F=10\ N$

So, the value of F in next 5 minutes is 10 N.

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