Question

A body of mass 5 kg is initially at restand a force of 50 N is applied on it. Calculate the distance covered by the body in 5 seconds.

Answer 1

ᎯᏁᏕᏯᎬᏒ

Given:-

Force (F) = 50 N

Mass (m) = 5 kg

Initial velocity (u) = 0

Time (t) = 5 s

To find:-

Distance (s)

Solution:-

$\boxed{ \rm</strong><strong>\</strong><strong>o</strong><strong>r</strong><strong>a</strong><strong>n</strong><strong>g</strong><strong>e</strong><strong>{Acceleration = \frac{Force}{mass}}}$

$\rm Acceleration = \frac{50}{5}</strong><strong>\</strong><strong>\</strong><strong>$

$\rm \red{Acceleration = 10</strong><strong>~</strong><strong>m {s}^{ - 2} }</strong><strong>\</strong><strong>\</strong><strong>$

$\green {.......................................................................}$

$\boxed{ \rm</strong><strong>\</strong><strong>o</strong><strong>r</strong><strong>a</strong><strong>n</strong><strong>g</strong><strong>e</strong><strong>{</strong><strong>D</strong><strong>i</strong><strong>s</strong><strong>t</strong><strong>a</strong><strong>n</strong><strong>c</strong><strong>e</strong><strong> = </strong><strong>ut</strong><strong>+</strong><strong> </strong><strong>\frac{</strong><strong>1</strong><strong> }{</strong><strong>2</strong><strong>} </strong><strong>×</strong><strong>a</strong><strong>t</strong><strong>²</strong><strong> </strong><strong>}}</strong><strong>$

$\rm</strong><strong> </strong><strong>s</strong><strong> =</strong><strong>(</strong><strong>0</strong><strong>×</strong><strong>5</strong><strong>)</strong><strong> </strong><strong>+</strong><strong> \frac{</strong><strong>1</strong><strong>}{</strong><strong>2</strong><strong>}</strong><strong>×</strong><strong>1</strong><strong>0</strong><strong>×</strong><strong>{</strong><strong>5</strong><strong>}</strong><strong>^</strong><strong>{</strong><strong>2</strong><strong>}</strong><strong>\</strong><strong>\</strong><strong>$

$\rm </strong><strong>s</strong><strong> = \frac{</strong><strong>1</strong><strong>}{</strong><strong>2</strong><strong>}</strong><strong>×</strong><strong>2</strong><strong>5</strong><strong>0</strong><strong>\</strong><strong>\</strong><strong>$

$\rm </strong><strong>s</strong><strong> = </strong><strong>1</strong><strong>2</strong><strong>5</strong><strong> </strong><strong>m</strong><strong>\</strong><strong>\</strong><strong>$

$\rm \red{</strong><strong>D</strong><strong>i</strong><strong>s</strong><strong>t</strong><strong>a</strong><strong>n</strong><strong>c</strong><strong>e</strong><strong> = </strong><strong>1</strong><strong>2</strong><strong>5</strong><strong>~</strong><strong>m</strong><strong> }</strong><strong>\</strong><strong>\</strong><strong>$

Answer 2

Given :

• Force (F) = 50 N
• Mass (m) = 5 kg
• Time (t) = 5 seconds
• Initial velocity (u) = 0 m/s

To find :

• Distance (s)

According to the question,

$\star \boxed { \sf \purple{Force\: (F) = ma}}$

$\sf{ \: \: \: : \implies50 =5 \times a}$

$\sf{ \: \: \: : \implies \: a = \cancel\frac{50}{5} {}^ { \: \: \: 10} }$

$\sf{ \: \: \: : \implies \: a = 10 \: ms {}^{ - 1} } \green \bigstar$

Now we will calculate the distance (s),

$\star \boxed{ \sf \red{s = ut + \frac{1}{2} \times {at}^{2} }}$

So,now according to the formula we will put the values

$\sf { \: \: \: : \implies \: s = 0 \times 5 + \frac{1}{2} \times {10 \times (5)}^{2} }$

$\sf { \: \: \: : \implies \: \frac{1}{2} \times 250 }$

$\sf{ \: \: \: : \implies125 \: m} \: \: \green \bigstar$

So,the distance is 125 m....