Question

a body of mass 5 kg is moving ina horizontal smooth surface at a velocity of 10m/ s constant force of 20 n in apply the body for 20s in the direction find the work done by the force

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Answer 1

Answer:

A body of mass 5 kg moving on a horizontal surface with a velocity of 10 ms^-1 comes to rest in 2s .

Answer 2

Answer:

Given :-

mass= 5kg

Initial velocity= 10 m persecond

Final Velocity= 0

Time= 2s

Required:-

F=?

Solution:-

First of all. To find acceleration we use first equation of motion.

a= vf - vi/ t

a= -5 m persecond square

Now Using Newton's second law of motion.

F= ma

F= -25N. The negative sign indicate that the force required to stop the body would be opposite to direction of the body.