Question

A body of mass 5 kg is moving with a uniform velocity of 10 m/s.It is acted by aforce of 20 N .what will be its velocity after 1 sec.

Answer 1

F=m(v-u)/t
20=5 (v-10)/1
20=5v-50
5v=20+50
5v=70
v=70/5
v=14m/s

Answer 2

m= 5kg
u=10m/S
F=20N
t=1 sec
V=? m/S

F = m×a
20=5 × a

a= 20/5 m/s square

a=(v-u)/t
4=(v-10)/1
v-10=4
V=4+10 m/s
V=14 m/s