Question

a body of mass 5 kg is moving with a velocity of 10 m/s .a force is appliced to it so that in 25 second ,it attains a velocity of 35 m/s .calculate the value of the force applied​

Answer 1

Answer:

F=ma

given, m=5kg a=(u=10m/s v=35m/s t=25sec) =( v-u)/t=(35-10)/25 = 1

F=ma

F=5×1=5N

Answer 2

Given that, a body of mass 5 kg is moving with a velocity of 10 m/s. (Here, mass of body is 5 kg and initial velocity of the body is 10 m/s).

Also given that, a force is appliced to it so that in 25 second ,it attains a velocity of 35 m/s. (Here, time is 25 sec and final velocity is 35 m/s).

We have to find the force applied on the body.

Using the First Equation Of Motion,

v = u + at

Substitute the known values,

35 = 10 + a(25)

35 - 10 = 25a

25 = 25a

1 = a

Therefore, the acceleration of the body is 1 m/s².

Now, force is defined as the product of mass and acceleration.

F = ma

Substitute the values,

F = 5 × 1

F = 5

Therefore, the force applied on the body is 5N.