A body of mass 5 Kg is moving with a velocity of 10 m/s. A force is applied on it so that in 25 s , it attains a velocity of 35 m/s. calculate the value of the force applied.
Answers
Answered by
5
m= 5kg
u= 10m/s
v= 35m/s
t= 25sec
we know,
f=m.a (a= v-u/t)
f= m(v-u/t)
f= 5(35-10/25)
f= 5N
u= 10m/s
v= 35m/s
t= 25sec
we know,
f=m.a (a= v-u/t)
f= m(v-u/t)
f= 5(35-10/25)
f= 5N
Answered by
29
Given,
mass,m=5kg
initial speed ,u=10m/s
final speed,v=35m/s
time taken, t=25sec
To calculate:- The value of force applied
Formula to be used:-
- acceleration =change in velocity/time
- force =mass×acceleration
Solution:-
- a=v-u/t
☆putting the all value
a=35-10/25
a=25/25
a=1 m/s²
- f=m×a
☆putting the value
f=m×a
f=5kg×1m/s²
f=5kg.m/s²or 5N
F=5N
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