a body of mass 5 kg is moving with a velocity of 10 m/s .find the ratio of initial kinetic energy and final kinetic energy. (a). if mass is doubled ...(b).it's velocity is made three times.
solve it please.!
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Answered by
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m1 = 5 kg
v1 = 10 m /s
KE(initial) = 1/2 x 5 x 10 x 10 = 250 joules
a)
m = 2m1 = 10 kg
v = v1 = 10 m/s
KE(final) = 1/2 x 10 x 10 x 10 = 500 joules
Ratio = KE(I) : (KE(f) = 250 : 500 = 1/2
b)
m = m1 = 5 kg
v = 3v1 = 30 m/s
KE(final) = 1/2 x 5 x 30 x 30 = 2250
Ratio = 250 : 2250 = 1 : 9 = 1/9
v1 = 10 m /s
KE(initial) = 1/2 x 5 x 10 x 10 = 250 joules
a)
m = 2m1 = 10 kg
v = v1 = 10 m/s
KE(final) = 1/2 x 10 x 10 x 10 = 500 joules
Ratio = KE(I) : (KE(f) = 250 : 500 = 1/2
b)
m = m1 = 5 kg
v = 3v1 = 30 m/s
KE(final) = 1/2 x 5 x 30 x 30 = 2250
Ratio = 250 : 2250 = 1 : 9 = 1/9
Nobita678:
ohhhh k thanks ...i was mistaken in calculation
A car and a truck have kinetic energies of 8*10^5 J and 9*10^5 respectively.If they brought to halt at the same distance,find the ratio of forces applied to both the vechiles.
answer this question above.
pretty please!
Yes but ask separately please :)
seperately?
Yes I got it ya
hmmm
??????
Answered by
0
Answer:
answer is 250J,, (a) 1:2 (b) 1:9
Explanation:
I. K. E = Initial kinetic energy
F.K.E = Final kinetic energy
Attachments:
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