Question

A body of mass 5 kg is moving with a velocity of 10 ms^-1 .find the force required to stop it in 2 seconds.

Answer 1

Hey user!!

GIVEN::- MASS= 5 KG .
INITIAL VELOCITY= 10M/S ..
TIME = 2 SECS..

THEIRFORE FORCE=???

NOW,, LET US CALCULTE THE ACCELARATION FIRST AS,,

A= V-U/T = 10-0/2= 5 M/S SQUARE..

NOW,, WE KNOW THAT FORCE= MASS×ACCELARATION= 5×5= 25 NEWTONS..

THEIRFORE, THE REQURIED FORCE= 25 NEWTONS..

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Answer 2

hello friend here is your answer.

FORCE = MASS × ACCELERATION.

THEREFORE ACCRLERATION = FINAL VELOCITY(V) - INITIAL VELOCITY(U) / TIME(T)

ACCELERATION = 10 - 0 / 2
ACCELERATION= 5 m/s^2

THEREFORE FORCE = MASS ×ACCELERATION
FORCE= 5 ×5
FORCE=25 NEWTON

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