a body of mass 5 kg is moving with a velocity of 10m/s is brought to rest by applying brakes . Work done by the brakes is?
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Answered by
2
work done =kinetic energy =1/2mv^2
=1/2×5×100
=250J
Answered by
0
here we have to calculate its initial k.e.
1/2*5*10*10
= 250 J
1/2*5*10*10
= 250 J
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