Question

A body of mass 5 kg is moving with momentum 10 kg m/s. A force of 20N acts on the body for 2s. What is the increase in kinetic energy after 2s.​

Answer 1

Answer:

M = mass * Velocity

v = momentum ÷ mass

velocity will be 2 m/s

KE = 1/2 mv 2

Ke = 1/2 * 5 * 2 * 2

KE = 10 Joules

if it is right than mark it as brainliest pls

Answer 2

t=10sec

10=5×v[P=mv]

v=2m/s

As F=0.2N

a=50.2m/s2=251m/s2[a=mF]

at t=0,KE=21×s×(2)2[KE=21mv2]

KEi=10J

Now, at t=10sec, vf=u+at

vf=g+251×10=2.4m/s2

∴KEf=21×5×(2.4)2

=14.4J

∴△KE=14.4−10

=4.4J

Hope it helps

Hope it helps Please mark brainliest

Hope it helps Please mark brainliest U won't loose much points