Question

A body of mass 5 kg is moving with the velocity 4 m/s brought to rest after covering a distance

10 m. Calculate retardation and retarding force.​

Answer 1

Answer:

a=-4/5 m/s^2, F= 4×10^-3N

Explanation:

given

m=5 kg = 5×10^-3 m, u=4m/sec, v=0,

distance(s)= 10 m

retardation (a)

v^2= u^2- 2as

a = v^2- u^2/2s

a= 0- 16/2×10

a= -16/20= -4/5 m/s^2

retarding force(F)= - ma = -5×10^-3×-4/5

F= 4×10^2 N