A body of mass 5 kg is moving with velocity of 10 ms-1
. What will be the ratio of its initial kinetic
energy and final kinetic energy, if the mass of the body is doubled and its velocity is halved?
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Answered by
0
Answer:
Answered by
1
Answer:
2:1
Explanation:
let, initial mass of the body ( m ) = 5 kg
initial velocity of the body ( v ) = 10 m/s
So , initial kinetic energy = 1/2 mv^2
= 1/2×5×(10)^2
= 250 J
now, m' = 2m
v' = v/2 m/s
hence, final kinetic energy will be
1/2 m'v'^2
= 1/2× 2m× (v/2)^2
= mv^2/4
put the values,
5×(10)^2/4 = 5×10×10/4
= 125J
Hence the ratio of initial kinetic energy to final kinetic energy will be 250/125 i.e., 2/1 or 2:1.
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