Question

A body of mass 5 kg is moving with velocity of v = (2i+6j) /s at t=0. after time t=2, velocity of body is (10i+6j), then change in momentum of body is

Answer 1

Given :-

Mass of the body = m = 5 Kg

Initial Velocity = u = (2i + 6j) ms-¹

Final Velocity = v = (10i + 6j) ms-¹

∆V = v - u

∆V = 10i + 6j - 2î - 6j

∆V = 8î ms-¹

Now,

∆P = m∆V

∆P = 5(8î)

∆P = 40î Kg ms-¹.

Hence,

Change in Momentum of body = ∆P = 40î Kgms-¹.