Question

A body of mass 5 kg is placed on a horizontal surface if the coefficient of static and kinetic friction at 0.5 and 0.4 then find the value of force of friction when applied horizontal force is 15 newton 25 and 35 newton

Answer 1

Given

Mass (M) = 10kg

Co-efficient of friction (K) = 0.5

Horizontal force = 100 N

g = 10m/s2

Solution

Normal reaction = M * g = 10 * 10

Normal reaction = 100N

Friction force (F) = K * 0.5 = 0.5 * 100 = 50N

F = Ma

50 = 10 * a

a = 5 m/s2

a = 5 m/s2 is the direction of force