Question

A body of mass 5 kg is taken from a
height of 3 m to 6 m. Find the increase
in the potential energy of the body
Take g = 10 N kg​

Answer 1

Answer:-

$\pink{\bigstar}$ Increase in Potential Energy is $\large\leadsto\boxed{\tt\purple{150 \: J}}$

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• Given:-

• Mass of the body = 5 kg

• Initial height of body = 3 m

• Final height of body = 6 m

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• To Find:-

• Increase in the Potential Energy = ?

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• Solution:-

We know,

$\pink{\bigstar}$ $\large\underline{\boxed{\bf\green{P.E = mgh}}}$

where,

• P.E = Potential Energy

• m = mass of the body

• g = acceleration due to gravity

• h = height of the body

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here,

• m = 5kg

• g = 10 m/s²

• h1 = 3m

• h2 = 6m

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✯ Applying the above Formula:-

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$\pink{\bigstar}$ $\underline{\boxed{\bf\green{P.E_{(final)} - P.E_{(initial)} = mg \times (h_2 - h_1)}}}$

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• Substituting in the Formula:-

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➪ $\sf P.E_{(increase)} = 5 \times 10 \times (6 - 3)$

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➪ $\sf P.E_{(increase)} = 50 \times 3$

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★ $\large{\bf\red{P.E_{(increase)} = 150 \: J}}$

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Therefore, the increase in Potential Energy will be 150 J.

Answer 2

${\bf{Given\::}}$

• Mass of a body is 5 kg.

• The body is taken from a height of 3 m to 6 m.

• Gravitational acceleration (g) = 10 m/s²

$\\ {\bf{To\: Find\::}}$

• The increase in potential energy of the body.

$\\ {\bf{Solution\::}}$

As we know that,

☛ Potential energy of a body is given as,

$\orange\bigstar\:{\Large\mid}\:\bf\blue{P.E\:=\:m\:g\:h\:}\:{\Large\mid}\:\green\bigstar$

☛ And increase in potential energy of a body (which denotes the height factor) is given as

$\red\checkmark\:\bf{P.E\:=\:m\:g\:(h_2\:-\:h_1)\:}$

Where,

• h₁ = 3 m

• h₂ = 6 m

➠ P.E = 5 × 10 × (6 - 3)

➠ P.E = 5 × 10 × 3

➠ P.E = 150 Joules

∴ The increase in potential energy of the body is 150 J.