Question

A body of mass 5 kg is taken from a
height of 3 m to 6 m. Find the increase
in the potential energy of the body
Take g = 10 N kg​

Answer 1

Answer:

the increase in the potential energy of the body is 150 J.

Explanation:

Given,

A body of mass 5 kg is taken from a height of 3 m to 6 m.

To find: The increase in the potential energy of the body

Solution:

Potential energy is defined as the energy of a body by virtue of it's position and configuration.

Potential Energy is given as:

P.E = mgh

where, m = mass of body , g = acceleration due to gravity, h  = height reached.

Since, the mass in the given question will be constant and height is varying. Then increase in P.E can be given as:

P.E = mg (hf - hi)

where, hf = final height = 6m, hi = initial height = 3m

Substituing the values,

P.E = 5 * 10 * ( 6 - 3)

P.E = 50 * 3

or, P.E = 150 J

Therefore, the increase in the potential energy of the body is 150 J.

Answer 2

• Given :-

• Mass of the body = 5 kg
• Initial height of body = 3 m
• Final height of body = 6 m

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• To Find :-

• Increase in the Potential Energy

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• Solution :-

We know,

$\pink{\bigstar} \large\underline{\boxed{\bf\green{P.E = mgh}}}$

where,

• P.E = Potential Energy
• m = mass of the body
• g = acceleration due to gravity
• h = height of the body

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here,

• m = 5kg
• g = 10 m/s²
• h1 = 3m
• h2 = 6m

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✯ Applying the above Formula:-

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$\pink{\bigstar}\underline{\boxed{\bf\green{P.E_{(final)} - P.E_{(initial)} = mg \times (h_2 - h_1)}}}$

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• Substituting in the Formula :-

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➪ $\sf P.E_{(increase)} = 5 \times 10 \times (6 - 3)$

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➪$\sf P.E_{(increase)} = 50 \times 3$

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★ $\large{\bf\red{P.E_{(increase)} = 150 \: J}}$

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Therefore, the increase in Potential Energy will be 150 J.