Physics, asked by gdivyansh320, 6 months ago

A body of mass 5 kg is taken from a height of 3m to 6m. Find he increase in potential energy.
g= 10N Kg^-1​

Answers

Answered by prateek24011
15

Answer:

Given,

Mass 1 = 5 kg

Height 1 = 3 m

g = 10m/s square

Now,

Potential Energy 1 = mgh

= 5 × 10 × 3 J

= 150 J

Given,

Mass 2 = 5 kg

Height 2 = 6 m

g = 10m/s square

Now,

Potential Energy 2 = mgh

= 5× 10 × 6 J

= 300 J

Therefore , Increase in Potential Energy = Potential Energy 2 - Potential Energy 1

= (300 - 150) J

= 150 J

Answered by Manjula29
2

Body mass = 5kg =m

          height 1= 3m =h1          

          height 2= 6m =h2       } All informations are supplied in the question

               g = 10N Kg^-1

potential energy 1  = mgh1      in fast case(1)

potential energy 2 = mgh2       in second case (2)

Increase in potential energy

  = (1) -(2)

=mgh2-mgh1

= mg (h2 - h1)

= 5×10×(6-3)

= (300-150) j

= 150J

Therefore the increase in potential energy is 150j.

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