Question

a body of mass 5 kg is thrown up vertically with a kinetic energy of 1000 J. If acceleration due to gravity is 10 ms^-2 , find the height at which the kinetic energy becomes half of the original value.

plz help it's urgent plz plz

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Answer 1

$5 \times 10 \times h = 1000j$

according to law of conservation of energy KE=PE so the h=20m

Answer 2

check the attachment

hope it helps