Question

a body of mass 5 kg is thrown up vertically with kinetic energy of 1000 Joule if the acceleration due to gravity is 10m/s .find out the height at which kinetic energy becomes half of its original value​

Answer 1

your answer is h=12.5

maybe it's helpful for you ☺️

Answer 2

Answer:

5 \times 10 \times h = 1000j

according to law of conservation of energy KE=PE so the h=20m