a body of mass 5 kg is thrown up vertically with kinetic energy of 1000 Joule if the acceleration due to gravity is 10m/s .find out the height at which kinetic energy becomes half of its original value
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your answer is h=12.5
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Answer:
5 \times 10 \times h = 1000j
according to law of conservation of energy KE=PE so the h=20m
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