Question

A body of mass 5 kg is thrown vertically upwards with a speed of 10 m/s. What is it's kinetic energy when it is thrown? Find it's potential energy when it reaches at the highest point. Also find the maximum height attained by the body. [g= 10 m/s²]​

Answer 1

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$\huge\mathfrak{Answer:-}$

⏩ Here, m= 5 kg, v= 10 m/s, g= 10 m/s²

→Initial kinetic energy of the body = 1/2 mv²

= 1/2 × 5 × (10)² = 250 J. Ans.

→ Potential energy at the highest point= Kinetic energy lost by the body = 250 J. Ans.

Now, as we know, mgh= P.E.,

5 × 10 × h = 250

Therefore,

→Height attained, h= 250/50 = 5 m. Ans.

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Hope it helps...:-)

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Answer 2

Answer:

hey mate here is your answer

Explanation:

mass=5kg

speed(u)=10m/s

speed(v)=0m/s

we know that height=distance(s)

by 2nd equation of motion

2as=v2-u2

2(-10)s=0-100

-20s=-100

:.s=-100/-20=100/20=5m=height attained

potential energy=mass*accn*height

=5*10*5

=250J

kinetic energy= 1/2 *m*v2

=1/2 *5*0

=0J

hope this helps

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