A body of mass 5 kg is thrown vertically upwards with a velocity of 20m/s. find the initial kinetc energy and kinetic and potential energy after 1 sec
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9
Kinetic energy =1/2 mv^2
Therefore, K.E.=1/2×5×20^2
=1000 joules.
The speed given =20m/s and time given =1 sec.
Therefore the distance travelled in one second is 20m.
The P.E after 1 sec =mgh=5×10×20 (considering g=10m/s^2)
=1000 joules.
Therefore, K.E.=1/2×5×20^2
=1000 joules.
The speed given =20m/s and time given =1 sec.
Therefore the distance travelled in one second is 20m.
The P.E after 1 sec =mgh=5×10×20 (considering g=10m/s^2)
=1000 joules.
Answered by
1
Step-by-step explanation:
Given ;
Mass : 5kg
velocity: 20m/s
. kinetic energy K.E. = 1/2 mv²
= 1/2 ×5 ×20 ×20
= 1000 joules
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