Question

A body of mass 5 kg moving with a speed of 3 ms. collides nca
body of mass 3 kg moving in the opposite direction at a speed
2 ms. The first body stops after the collision. The final velochy
second body is​

Answer 1

3m/s

total momentum before the collision = total momentum aftre the collision

m1u1 + m2u2 = m1v1+ m2v2

u1 = 3m/s

u2 = -2m/s

V1 = 0

V2 =?

m1 = 5kg

m2 = 3kg

now, 5*3 + 3*-2 = 5*0 + 3v2

V2 = 9/3 = 3

V2 = 3m/s

Answer 2

Answer:

m1= 5kg

m2= 3kg

u1= 3m/s

u2= -2m/s

v1= 0

v2= ?

from,

m1u1+m2u2=m1v1+m2v2

v2 = 3m/s