A body of mass 5 kg starts acceletaring to 8m/s in 20 and its mass is 5kg. Find the force applied.
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It's easy question..........!!!!!☺️☺️
Mass = 5 kg (given)
Initial velocity (u) = 0 m/s
Final velocity (v) = 8 m/s
time (t) = 20 seconds.
Acceleration (a) = v-u/t = 8-0/20 = 8/20
= 0.4 m/s^2
Now, from newton's second law, we get
Force (F) = Mass (m) × acceleration (a)
=> F = (5×0.4) Newton
=> F = 2 Newton.
Hence, the force applied is
Mass = 5 kg (given)
Initial velocity (u) = 0 m/s
Final velocity (v) = 8 m/s
time (t) = 20 seconds.
Acceleration (a) = v-u/t = 8-0/20 = 8/20
= 0.4 m/s^2
Now, from newton's second law, we get
Force (F) = Mass (m) × acceleration (a)
=> F = (5×0.4) Newton
=> F = 2 Newton.
Hence, the force applied is
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