Question

A body of mass 5 kg starts and rolls down 32m of an inclined plane in 4s. Find the force acting on the body?

Answer 1

Answer:

S = ut + 1/2at²

Here,

u = 0

S = 32 m

t = 4 s

then,

32 = 0 + 1/2×a×16

32 = 8a

a = 4 m/s²

Now,

Force = Mass × Acceleration

Mass is Given 5 Kg

and Acceleration is 4 m/s²

Then,

Force = 5 Kg × 4 m/s²

= 20 kg m/s²

= 20 Newton (N)

Answer 2

$\large \bold{ \underline{ \underline{ \: Answer : \: \: \: }}}$

$\to$ Force = 20 N

$\large \bold{ \underline{ \underline{ \: Explaination : \: \: \: }}}$

Using second equation of motion ,

$\fbox{ \fbox{ \large{ \bold{x = ut + \frac{1}{2} a {t}^{2} </p><p>}}}}$

$\to32 = 0 \times 4 + \frac{1}{2} \times 16a \\ \\ </p><p> \to 32=8a \\ \\ </p><p></p><p> \to a=4 \: \: m/{s}^{2} </p><p>$

Now , We know that

$\large \bold{ \fbox{ \fbox{ \bold{ \: \: \: Force = M × A \: \: \: }}}}$

$\to$ Force = 5 × 4

$\to$ Force = 20 N