Question

A body of mass 5 kg starts from rest and attains a speed of 4 m/s in a horizontal distance of
12 m. Assume coefficient of friction is 0.25. Find out the minimum force P acting on the
body.​

Answer 1

Answer:

.83 N

Explanation:

m = 5 kg

v = 4 m/s

u = 0 m/s

S = 12m

$v^{2} - u^{2} = 2as$

$a = \frac{v^{2} - u^{2} }{2s}$ = 16 /24 = 2 /3 $m/s^{2}$

P = μ m a

  = .66 x 1.25 = .83 N