Question

A body of mass 5 kg thrown vertically upwards with an initial velocity of 50 m/s what will be its potential energy at the end of 5 s​

Answer 1

Explanation:

Given, m = 5kg, u= 50m, t = 5s,

g = 10m

Height covered by the body in 5 s is h = ut + ${{g}^{2}}$

= 50x5 - 1/2 x10x 5 x 5

= 250 - 125= 125 m

Therefore, PE of the body after 5 s

= mgh = 5 X 10 x 125 = 6250J

Answer 2

Given:-

• Mass of body,m = 5 kg

• Initial velocity ,u = 50m/s

• Time taken ,t = 5s

• Acceleration due to gravity ,g = 10m/s²

To Find:-

• Potential Energy ,PE

Solution:-

Firstly we calculate the height attained by body in 5 second.

Using 2nd Equation of Motion

• h = ut + 1/2gt²

h is the height attained by body

g is the acceleration due to gravity

u is the initial velocity

t is the time taken

Substitute the value we get

➨ h = 50×5 + 1/2 (-10) × 5²

➨ h = 250 + (-5) × 25

➨ h = 250 - 125

➨ h = 125 m

The height attained by the body is 125 m

Now, Calculating Potential Energy

• PE = mgh

Where

PE is the Potential Energy

m is the mass of body

h is the height attained by body

Substitute the value we get

➨ PE = 5×10 × 125

➨ PE = 50×125

➨ PE = 6250 J

Therefore, the potential energy of the body at the end of 5 second is 6250 Joules.