Question

A body of mass 5 kg traverses in successive sexonds distances of 8,9,10 meters. The force acting on it is
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Answer 1

Answer:

Given,

m=5kg

A body traverses in successive second distance of 8.9.10 meter as an average velocity increases at the rate of 1m/s2.

acceleration, a=1m/s

The force acting on the body is,

F=ma

F=5×1=5N