A body of mass 5 kg, which is initially at rest, is moved by a horizontal force of I0N on a smooth horizontal surface. Calculate the work done by the body in 2s
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work done is f*s. f=10 N there fore s=....
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F = ma
10= 5a
a = 2 m/s
t = 2 sec.
s= ut + 1/2.a.t²
s= 0 X 2 + 1/2 X 2 X 2²
s= 4 m
W= Fs
W= 10 X 4
W= 40 Joules
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