A body of mass 50 kg is falling from a height 100 m. After it has fallen a height 50 m, it will possess. Which energy will be used.
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Let a body of mass ′m′ placed at a height ′h′ above the ground, start falling down from rest.`
When the body falls from a height h to h/2, the potential energy is given as 2mgh.
The body covers the distance h/2 with a velocity v. We make use of the third equation of motion to obtain velocity of the body.
v2−u2=2aS
Here, u=0,a=g and S=x
v2−0=22gh,thatisv2=gh
Kinetic energy = 21mv2
That is, K.E=2mgh
Hence, at height h/2 the energy possessed is half potential energy and half the kinetic energy.
Explanation:
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