Question

A body of mass 50 kg is pulled by a rope of length
6 m on a surface by a force 106 N applied at the
other end. The linear density of the rope is
0.5 kg/m. The force acing on 50 kg mass is :
(a) 50 N (b) 100 N (c) 150 N (d) 200 N​

Answer 1

Answer:

b). 100 N

Explanation:

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Mass of rope = 6×0.5 = 3 Kg

Total Mass = 50+3 = 53 Kg

Acceleration = F/m = 106/53 = 2 m/s^2

Force needed for pulling rope = 3×2 = 6N

Net Force 53×2 = 106 N

So , force acting on 50 Kg =106 -6 =100N

Answer 2

Answer:

100 N

Explanation:

1 m → 0.5 Kg

8m → 8×0.5 = 4 kg

a=f/m

 =108/50+4

 = 2 m/s²

F(50 kg)= 50 ×2

             = 100 N