Question

A body of mass 50 kg suspended from a spring balance attached to the celling of an elevator what is the reading of the balance if the elevator moves? A, upward with an acceleration of 3 m/s. B, down ward with an acceleration of 2 m/s. C, with constant velocity.

Answer 1

Answer:

As the lift is freely falling, thus its acceleration in down ward direction  a=g

Let the mass of the body be m and force acting on it due to spring be F.

Writing equation of motion for the body :  ma=mg−F

Or    mg=mg−F

⟹ F=0

Thus  no force is acting on the body due to spring, so the reading of the spring balance is zero.



please mark it as brainliest

Answer 2

Answer:

As the lift is freely falling, thus its acceleration in down ward direction a=g

Let the mass of the body be m and force acting on it due to spring be F.

Writing equation of motion for the body : ma=mg−F

Or mg=mg−F

⟹ F=0

Thus no force is acting on the body due to spring, so the reading of the spring balance

hope this is help you☺ friend