Question

A body of mass 500 g, initially at rest, is acted upon
by a force which causes it to move a distance of
4 m in 2 s, Calculate the force applied.​

Answer 1

Given :

Mass of the body(m) = 500 g = 0.5 kg

Initial velocity (u) = 0 m/s

Distance travelled (s) = 4m

Time = 2s

To find :

Force applied

Solution :

Final velocity (v) is given by the formula :

$\tt \blue{velocity = \dfrac{distance}{time}}$

v = 4/ 2

v = 2 m/s

From first equation of motion,

v = u + at

2 = 0 + a (2)

2 = 2 a

a = 2/2

a = 1 m/s²

Force is given by the formula :

F = ma

where m = mass and a = acceleration

= 0.5 × 1

= 0.5 N

____________________

Force is a vector quantity .

It is given as the product of mass and acceleration .

Its SI unit is Newton denoted by N .