Question

A body of mass 500 g, initially at rest, is acted upon
by a force which causes it to move a distance of 4
m in 2 s, Calculate the force applied.
​

Answer 1

Step-by-step explanation:

Force = 0.5N

Given :

$\: Mass = 500g = \: \: \frac{500}{1000} kg = 0.5kg$

Initially at rest (u) = 0 m/s

distance = 4m

time = 2sec

$velocity (v) = \frac{distance}{time} = \frac{4}{2} = 2 \frac{m}{s}$

$acc. = \frac{v - u}{t} = \frac{2 - 0}{2} = \frac{2}{2} = 1m {s}^{ - 2}$

Now

$force = mass \times acc.$

$Force = 0.5 × 1 = 0.5N$