Question

A body of mass 500 g , initially at rest is acted upon by a force which causes it to move a distance 4m in 2s. Calculate the force applied.

Answer 1

A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.

here, initial velocity , u = 0
time taken , t = 2 sec
distance covered , s = 4m

use formula , S = ut + 1/2 at²
4 = 0 + 1/2 × a × 2²
4 = 2a => a = 2 m/s²

we know, from Newton's 2nd law of motion,
F = ma
here, m = 0.5kg and a = 2m/s²
so, F = 0.5 × 2 = 1N

hence, force applied 1N

Answer 2

Hey Mate!!!

Here's your answer.

initial velocity , u = 0

time taken , t = 2 sec

distance covered , s = 4m

S = ut + 1/2 at²

4 = 0 + 1/2 × a × 2²

4 = 2a

a = 2 m/s²

F = ma

m = 0.5kg and a = 2m/s²

so, F = 0.5 × 2 = 1N

I hope it helps.

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