Question

A body of mass 500 g, initially at rest, is acted upon
by a force which causes it to move a distance of
4 m in 2 s, Calculate the force applied​

Answer 1

Answer :-

The amount of force applied is 1 N .

Explanation :-

We have :-

→ Mass of the body = 500 g = 0.5 kg

→ Distance covered = 4 m

→ Time taken = 2 s

→ Initial velocity of the body = 0

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Firstly, let's calculate acceleration of the body by using the 2nd equation of motion.

s = ut + ½at²

⇒ 4 = 0 × 2 + ½ × a × (2)²

⇒ 4 = 0 + ½ × a × 4

⇒ 4 = 2a

⇒ a = 4/2

⇒ a = 2 m/s²

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Now, by Newton's 2nd law of motion :-

F = ma

⇒ F = 0.5 × 2

⇒ F = 1 N

Answer 2

Answer:

Question :-

• A body of mass 500 g, initially at rest, is acted upon by a force which causes it to move a distance of 4 m in 2 s, Calculate the force applied

Given :-

• A body of mass 500 g, initially at rest, is acted upon by a force which causes it to move a distance of 4 m in 2 s.

To Find :-

• Calculate the force applied.

Solution :-

Given in the question :

$\curlyeqsucc$ Mass of the body :-

$\implies$ 500 g

$\implies$ 0.5 kg

$\curlyeqsucc$ Distance covered = 4 m

$\curlyeqsucc$ Time taken = 2 seconds

$\curlyeqsucc$ Initial velocity of the body = 0 m/s

Firstly, let's calculate acceleration of the body by using the 2nd equation of motion,

$\red{ \boxed{\sf{s = ut + \dfrac{1}{2}at^2}}}$

$\implies$ 4 = 0 × 2 + ½ × a × (2)²

$\implies$ 4 = 0 + ½ × a × 4

$\implies$ 4 = 2a

$\implies$ a = 4/2

$\implies$ a = 2 m/s²

Now, by Newton's 2nd law of motion,

$\red{ \boxed{\texttt{F = ma}}}$

$\implies$ F = 0.5 × 2

$\implies$ F = 1 Newton

Therefore, the force applied is 1 N