Question

A body of mass 500 g is resting on a frictionless surface. Calculate the distance travelled by it in 10 seconds when acted upon by a force of 10^ -2 N.​

Answer 1

Answer:

Given:-

Mass = 0.5 kg

Force = 0.01 N

Time = 10 s

Initial velocity = 0 m/s

To find:-

Distance = x

Formulae to be used:-

Force = mass*acceleration

s = ut + (1/2)*a*t²

How to find:-

Force = mass*acceleration

0.01 = 0.5 * a

a = 0.02 m/s²

Now by applying, s = ut + (1/2)*a*t²

s = (0*10) + (1/2)*(0.02)*10²

s = 0 + (0.01)*100

s = 0.01*100

s = 1 m

Hence the distance travelled by the body before it goes to rest is 1 m.

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Answer 2

$\sf\huge{\underline{\underline{Solution}}}-$

Here,

• $\sf{F = 0.01 N}$
• $\sf{m = 500 g= 500/1000 kg= 0.5 kg}$

∵ $\sf\red{F = ma}$........................$\red{(1)}$

Substituting the values in Eqn. (1)

$\sf{a = F/m}$

$\sf\: \: \:= 0.01 N/0.5 kg$

$\sf \: \: \:= 0.2 m/s$²

∵ $\sf\red{S = ut + 1/2 at}$²........................$\red{(2)}$

Here,

• $\sf{u = 0}$
• $\sf{t = 10 s}$
• $\sf{a = 0.2 m/s}$²

Substituting the values in Eqn. (2)

$\sf{S = 0 × 10 + (1/2)0.2 × (10)}$²

$\sf\: \: \:{= 1 × 0.01 × 100}$

$\sf\: \: \:={\boxed{\underline {\sf\red{1 m}}}}.$

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