A body of mass 500 is rotating in a vertical circle of radius 1m what is the difference in its kinetic energy at the top and the bottom of the circle ?
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hey dear here is ur answers
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acccording to work energy theoram,
∆K.E.=W and work here is done by the gravation force.
→∆K.E.=W=mg(2r)
→1×5×2(1)=10J
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