Question

A body of mass 500 kg kept at rest breaks
into two parts due to internal forces. One
part
of mass 200 g is found to move at the
speed of 10 m/s towards the east. What will
be the velocity of the other part?
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A boy of mace so​

Answer 1

Answer:

Velocity of other part will be 6.67m/s in opposite side i.e towards west.

Step-by-step explanation:

Mass of one part = 200g

Other part will be of 500g - 200g = 300g

Velocity of first mass = 10m/s

Let the velocity of other part be =x

From Conservation of linear momentum

V1M1 +V2M2 = 0

200 x 10 = - 300x

x = -6.67m/s