a body of mass 500g initially at rest is acted upon by a force which causes it to move a distance of 4m in 2s, calculate the force applied
Answers
Answer:
1 N
Explanation:
Given :
Mass of body is 500 g .
In term of kg is 0.5 kg.
Initially at rest mean u = 0
Distance is 4 m
Time = 2 sec .
We know :
F = m a
also know a = v - u / t
substituting this value
F = m ( v - u / t ) [ u = 0 ]
F = m v / t
Putting given values we get :
F = 0.5 × 4 / 2 N
F = 0.5 × 2 N
F = 1 N
Thus we get applied force is 1 N.
Given :
Initial velocity (u) = 0 m/s
(As box is at rest)
Mass of box (m) = 500 g
Distance (s) = 4 m
Time (t) = 2 sec
Find :
Force (F) applied.
Solution :
We know that
s = ut + 1/2 at²
We have
- s = 4 m
- u = 0 m/s
- t = 2 sec
- a = ?
Substitute the known values in above formula
=> 4 = 0(2) + 1/2 a(2)²
=> 4 = 1/2 × 4a
=> 4 = 2a
=> a = 2
Acceleration (a) = 2 m/s².
Now,
From Newton's Second law of motion
F = ma
We have
- m = 500 g = 0.5 kg
- a = 2 m/s²
Substitute the known values in above formula
=> F = 0.5 × 2
=> F = 1 N
∴ Force = 1 N.