Question

A body of mass 500g,initially at rest, is acted upon by a force which causes it to move a distance of 4m in 2s, calculate the force applied..​

Answer 1

Explanation:

A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.

A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.here, initial velocity , u = 0

A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.here, initial velocity , u = 0time taken , t = 2 sec

A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.here, initial velocity , u = 0time taken , t = 2 secdistance covered , s = 4m

A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.here, initial velocity , u = 0time taken , t = 2 secdistance covered , s = 4muse formula , S = ut + 1/2 at²

A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.here, initial velocity , u = 0time taken , t = 2 secdistance covered , s = 4muse formula , S = ut + 1/2 at²4 = 0 + 1/2 × a × 2²

A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.here, initial velocity , u = 0time taken , t = 2 secdistance covered , s = 4muse formula , S = ut + 1/2 at²4 = 0 + 1/2 × a × 2²4 = 2a => a = 2 m/s²

A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.here, initial velocity , u = 0time taken , t = 2 secdistance covered , s = 4muse formula , S = ut + 1/2 at²4 = 0 + 1/2 × a × 2²4 = 2a => a = 2 m/s²we know, from Newton's 2nd law of motion,

A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.here, initial velocity , u = 0time taken , t = 2 secdistance covered , s = 4muse formula , S = ut + 1/2 at²4 = 0 + 1/2 × a × 2²4 = 2a => a = 2 m/s²we know, from Newton's 2nd law of motion,F = ma

A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.here, initial velocity , u = 0time taken , t = 2 secdistance covered , s = 4muse formula , S = ut + 1/2 at²4 = 0 + 1/2 × a × 2²4 = 2a => a = 2 m/s²we know, from Newton's 2nd law of motion,F = mahere, m = 0.5kg and a = 2m/s²

A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.here, initial velocity , u = 0time taken , t = 2 secdistance covered , s = 4muse formula , S = ut + 1/2 at²4 = 0 + 1/2 × a × 2²4 = 2a => a = 2 m/s²we know, from Newton's 2nd law of motion,F = mahere, m = 0.5kg and a = 2m/s²so, F = 0.5 × 2 = 1N

A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.here, initial velocity , u = 0time taken , t = 2 secdistance covered , s = 4muse formula , S = ut + 1/2 at²4 = 0 + 1/2 × a × 2²4 = 2a => a = 2 m/s²we know, from Newton's 2nd law of motion,F = mahere, m = 0.5kg and a = 2m/s²so, F = 0.5 × 2 = 1Nhence, force applied 1N

Answer 2

$\sf \: Given, \\ \sf</p><p>Mass(m) = 500 g \: to \: kg \\ \sf \: = \: \frac{5 \cancel0 \cancel0}{10 \cancel0 \cancel0} \: = \: 0.5 \: kg\\ \sf</p><p>Distance (d) = 4 m \\ \sf</p><p>Time(t) = 2 s \\ \sf \: </p><p>Initial \: velocity (u) = 0 m/s \\ \\ \boxed{ \blue{ \underline{\sf{ \implies final \: velocity(v) \: = \: \frac{d}{t} \: }}}} \\ \sf \: = \: \frac{ \cancel4 \: ^{2} m}{ \cancel2s} \\ \sf \: = \: 2 {m}^{ - 2} \\ \\ \boxed{ \blue{ \underline{ \sf{ \implies{acceleration(a) \: = \: \frac{v - u}{t} }}}}} \\ \sf \: = \: \frac{2 - 0}{2} \\ \sf \: = \frac{ \cancel2}{ \cancel2} \: m {s}^{ - 2} \\ \sf \: = \: 1 \: m {s}^{ - 2} \\ \\ \boxed{ \blue{ \underline{ \sf{ \implies{force \: = \: ma}}}}} \\ \sf \: = \: 0.5 \: kg \: \times 1 \: m {s}^{ - 2} \\ \boxed{ \red{ \underline{\sf \: = \: 0.5 \: N}}}</p><p>$