Question

A body of mass 500g,initially at rest,is acted upon by a force which cause it to move a distance of 4m in 2s.Calculate the force applied .

Answer 1

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★ A body of mass 500g,initially at rest,is acted upon by a force which cause it to move a distance of 4m in 2s.Calculate the force applied .




→ A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.

→ here, initial velocity , u = 0
→ time taken , t = 2 sec
→ distance covered , s = 4m

→ use formula , S = ut + 1/2 at²
4 = 0 + 1/2 × a × 2²
4 = 2a => a = 2 m/s²

→ we know, from Newton's 2nd law of motion,
F = ma
here, m = 0.5kg and a = 2m/s²
so, F = 0.5 × 2 = 1N

hence, force applied 1N



❣️hope this helps uh ❣️

Answer 2

Given:
M=500g=0.5kg.
U=0ms-1
T=2s.
D=4m.
Solution:
V=d/t
=4/2=2ms-1
As we know,
F=m(v-u)/t
F=0.5*(2-0)/2
F=5/10
F=1/2
Therefore F= 0.5N