A body of mass 500g is at rest on a frictionless horizontal surface. Calculate the distance travelled by it in 10s when acted upon by a force of 10N
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Answer:
Distance traveled in 10 seconds = 1 metre
Explanation:
Given :
A body of mass 500 g is at rest on a frictionless surface.
When the body is acted upon by a force of 10^{-2}N,
then find distance traveled by the body in 10 seconds .
Solution :
We know that,
Force = Mass × Acceleration ( F = ma )
Force (F) = 10^{-2}N = 0.01 N
Mass (m) = 500 g = 0.5 kg
⇒ F = ma
⇒ 0.01 = 0.5a
⇒ \frac{0.01}{0.5} = a ⇒ a = 0.02 m/s²
We also knew that,
Distance traveled (s) = ut + ¹/₂ at² (here , s meant distance travelled)
here u = 0 m/s
t = 10 seconds.
a = 0.02 m/s²
⇒ s = ut +\frac{1}{2} at^2
⇒ s = 0 \times 10 +\frac{1}{2} \times 0.02 \times (10)^2
⇒ s = 0 + 0.01 \times 100 = 1 m
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